16=-16t^2+79t+7

Solution for 16=-16t^2+79t+7 equation:

16=-16t^2+79t+7

We move all terms to the left:

16-(-16t^2+79t+7)=0

We get rid of parentheses

16t^2-79t-7+16=0

We add all the numbers together, and all the variables

16t^2-79t+9=0

a = 16; b = -79; c = +9;
Δ = b2-4ac
Δ = -792-4·16·9
Δ = 5665
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-79)-\sqrt{5665}}{2*16}=\frac{79-\sqrt{5665}}{32}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-79)+\sqrt{5665}}{2*16}=\frac{79+\sqrt{5665}}{32}
$